## Search found 22 matches

- Sun Sep 14, 2014 11:35 am UTC
- Forum: Logic Puzzles
- Topic: Tournament Scheduling
- Replies:
**6** - Views:
**3208**

### Re: Tournament Scheduling

One interesting sub-question is: Ignoring games completely, and forgetting the labels on people and times, how many genuinely different schedules are there? I.e. in how many genuinely different ways can 6 people be scheduled to meet pairwise in five time slots so that each person meets every other e...

- Fri Aug 29, 2014 7:55 am UTC
- Forum: Logic Puzzles
- Topic: Hard number sequence: 4, 8, 16, 26, 41, 57, 79, 104, 138,...
- Replies:
**16** - Views:
**8124**

### Re: Hard number sequence: 4, 8, 16, 26, 41, 57, 79, 104, 138

A compromise between the line breaks being important and purely cosmetic is if they are hinting at the Fibonacci sequence (5, 3, 2, 1, 1). EDIT: Also, continuing PsiSquared's note : The ratio between successive terms is 2.00000, 2.00000, 1.62500, 1.57692, 1.39024, 1.38596, 1.31646, 1.32692, ...

- Thu Aug 28, 2014 9:27 am UTC
- Forum: Logic Puzzles
- Topic: Illustrated Math Function
- Replies:
**8** - Views:
**8545**

### Re: Illustrated Math Function

An obvious guess for a bit of manipulation of the second image is

**Spoiler:**

- Wed Aug 27, 2014 10:55 am UTC
- Forum: Logic Puzzles
- Topic: Hard number sequence: 4, 8, 16, 26, 41, 57, 79, 104, 138,...
- Replies:
**16** - Views:
**8124**

### Re: Hard number sequence: 4, 8, 16, 26, 41, 57, 79, 104, 138

I would expect the formatting into rows to be significant, and possibly a hint that a row is missing.

Is it just a coincidence that...

Is it just a coincidence that...

**Spoiler:**

- Tue Aug 26, 2014 1:03 pm UTC
- Forum: Logic Puzzles
- Topic: Illustrated Math Function
- Replies:
**8** - Views:
**8545**

### Re: Illustrated Math Function

My thoughts: The first image is 0 The second image somehow involves x? Though I guess its supposed to be a number. I'm pretty sure this is an x-ray of a large truck. Maybe 18 (for 18 wheeler)? The third images is either pi^2 or pi/6 Just getting the juices flowing Interesting observatio...

- Mon Aug 11, 2014 12:32 pm UTC
- Forum: Logic Puzzles
- Topic: 5 word puzzle
- Replies:
**3** - Views:
**2812**

### Re: 5 word puzzle

Here's what I've noticed. Words seem to reuse three of the letters that occur in the word preceding them. The exception is the last word, which reuses only one (S). All those letters that occur more than once are reused in this way in multiple sequential words. This is all I have found for ...

- Sat Aug 02, 2014 9:38 am UTC
- Forum: Logic Puzzles
- Topic: Two interesting puzzles (1 easy, 1 unsolved)[Solutions,etc.]
- Replies:
**5** - Views:
**4796**

### Re: Two interesting puzzles (1 easy, 1 unsolved)[Solutions,e

Not sure if relevant, but I recognise the first three three-letter combinations as... ...airport codes ARN - Stockholm (Arlanda) BCN - Barcelona ZRH - Zurich And the remainders would be KRT - Khartoum CPT - Cape Town BTS - Bratislava RUH - Riyadh DKR - Dakar Perhaps drawing lines between the cities ...

- Sat Aug 02, 2014 9:04 am UTC
- Forum: Logic Puzzles
- Topic: Need help with a puzzle "InTerCoMMuniCaTiOns AlPhabEt"
- Replies:
**2** - Views:
**2137**

### Re: Need help with a puzzle "InTerCoMMuniCaTiOns AlPhabEt"

Nice! I'm quite sure this is the answer:

**Spoiler:**

**Spoiler:**

- Sat May 19, 2012 11:51 am UTC
- Forum: Logic Puzzles
- Topic: Knights and Knaves Revisited
- Replies:
**5** - Views:
**2977**

### Re: Knights and Knaves Revisited

There are x knights, y knaves, and z randoms (that all know what each other are). The randoms just randomly say yes or no. You are given x,y,z, and you need to find out who is who in the minimum amount of questions. Also, if there are enough randoms, then it is possible that the problem is unsolvab...

- Fri May 18, 2012 6:52 am UTC
- Forum: Logic Puzzles
- Topic: Knights and Knaves Revisited
- Replies:
**5** - Views:
**2977**

### Re: Knights and Knaves Revisited

Do the knights (and knaves) know knights from knaves? I would guess so, or else you can only gain information about the person you're asking and hence you need to ask N-1 people. Given this, it seems there's this solution: Use a wrapper such as "If I asked you X, what would you answer?&quo...

- Thu Mar 29, 2012 9:20 pm UTC
- Forum: Logic Puzzles
- Topic: The Disgruntled Alien Visitor
- Replies:
**9** - Views:
**5297**

### Re: The Disgruntled Alien Visitor

We could be more efficient if we could figure out how to find out answers to our questions without knowing which of the three responses are which. Then we don't need to waste two questions at the beginning. E.g. if the possible responses are da/ja meaning yes/no then asking "Is it true that...

- Tue Sep 27, 2011 8:45 am UTC
- Forum: Forum Games
- Topic: Solve this Mathematical Puzzle
- Replies:
**36** - Views:
**4573**

### Re: Solve this Mathematical Puzzle

I am posting the answer to this puzzle. The answer is 6480. After this if you cant calculate, I will give you the calculation. Since "6 + 5 + 1" = 6480 = 2^4 * 3^4 * 5, I'd guess it's "a + b + c "= a^(b-c) * b So it was only a coincidence that c = a^(b-c-1) in th...

- Wed May 25, 2011 7:10 pm UTC
- Forum: Logic Puzzles
- Topic: Chain of Circles
- Replies:
**15** - Views:
**5954**

### Re: Chain of Circles

I think I have a solution: By rotational symmetry of circles, the optimal placement is to have all centres on a line. If circle #n has radius r n and distance d n to the next circle (between centres), then we have the relationship r n 2 = d n 2 + r n+1 2 . Hence we have 1 = r 0 2 = d 0 2 + d...

- Tue May 24, 2011 10:49 pm UTC
- Forum: Logic Puzzles
- Topic: Humans and zombies - a knights-and-knaves style puzzle.
- Replies:
**3** - Views:
**2039**

### Re: Humans and zombies - a knights-and-knaves style puzzle.

Simpler, less general, solution for first bit: 1. Are you telling the truth? HT: (Yes) Yes HL: (No) Yes ZT: (Yes) No ZL: (No) No Alternative phrasing of undecim's general solution: You are human XOR you are telling the truth XOR statement Q ? HT: (Yes XOR Yes XOR ...

- Fri Apr 29, 2011 7:40 pm UTC
- Forum: Logic Puzzles
- Topic: How many prisoners?
- Replies:
**112** - Views:
**46178**

### Re: How many prisoners?

Here is a strategy my friend came up with, which solves the problem with probability 1 (so only "almost surely") provided each prisoner has a random number generator: First, find an upper bound B for the number of prisoners, as described earlier. We also use the method to "ping" ...

- Mon Apr 25, 2011 3:49 pm UTC
- Forum: Logic Puzzles
- Topic: How many prisoners?
- Replies:
**112** - Views:
**46178**

### Re: How many prisoners?

Assuming the e-mail cannot name specific prisoners, so that they all use the same strategy: Even if the strategy contains randomness, there is always a non-zero chance that up to day k, all prisoners have done the exact same thing. So no matter what strategy, they will not in finite time be able to ...

- Sun Mar 20, 2011 9:19 am UTC
- Forum: Logic Puzzles
- Topic: Infinite Clones
- Replies:
**66** - Views:
**7356**

### Re: Infinite Clones

The answer may depend on whether we regard the cloning process as preserving the activator and creating a copy of him, or splitting him into two identical copies. In the first case, we could try to argue that only clones which have been "created" at some point count. This corresponds to re...

- Fri Apr 16, 2010 11:47 am UTC
- Forum: Logic Puzzles
- Topic: Is This Even Possible?
- Replies:
**77** - Views:
**26992**

### Re: Is This Even Possible?

Proof of impossibility for unknown comparable words with random answering yes/no randomly: Let the words for yes and no be X < Y. There are eight answer strings, out of which two are indistinguishable: XXX=YYY. These must be assigned to 6 cases. There is nothing to compare the first answer to, so it...

- Wed Apr 14, 2010 2:33 pm UTC
- Forum: Logic Puzzles
- Topic: Is This Even Possible?
- Replies:
**77** - Views:
**26992**

### Re: Is This Even Possible?

I don't believe that argument is correct. The first question may not provide us with any immediate information, but we may learn enough from the other two questions to go back and interpret that first answer. What I'm saying is that any deterministic algorithm will be of the following form (in PHP)...

- Tue Apr 13, 2010 8:39 pm UTC
- Forum: Logic Puzzles
- Topic: Is This Even Possible?
- Replies:
**77** - Views:
**26992**

### Re: Is This Even Possible?

Didn't Nitrodon prove it's impossible when you don't know the words ahead of time? About the second case: The first answer gives no information beyond identifying one word for yes or no. The yes/no words can be described as "the answer given to the first question" and "the answer not ...

- Fri Jun 26, 2009 11:52 am UTC
- Forum: Logic Puzzles
- Topic: Yet another hat problem
- Replies:
**10** - Views:
**2557**

### Re: Yet another hat problem

When I was first presented with this problem, I was given a sight of 3, and my friends and I spent some years failing to solve it before finding out it should have been 4. Therefore, I am personally convinced (but cannot prove) that 3 is not possible: Consider a row of clones, say #1, #2, #3, #4, #5...

- Fri Jun 26, 2009 6:38 am UTC
- Forum: Logic Puzzles
- Topic: Yet another hat problem
- Replies:
**10** - Views:
**2557**

### Re: Yet another hat problem

Here is a solution for when gaps are left and sight is 4. The system we wish to set up is that n, n+1 know their colours while n+2 knows the relation between n+1 and n+2, for n incrementing in steps of two. "Given" n, let n,n+1 (who both know their colours and see n+3,n+4) guess co...