## Search found 4 matches

Mon Jul 01, 2019 9:59 am UTC
Forum: Individual XKCD Comic Threads
Topic: 2164: "Glacier"
Replies: 15
Views: 1909

### Re: 2164: "Glacier"

That's the problem with the xkcd forumites, you end up writing in Python. You, sir, have just won one (1) imperial internets (slightly smaller than a metric internet, but is divisible by 12). I hope that's British Imperial. I now learn that Python the language was named after* the comedy, so my wit...
Wed Jun 26, 2019 8:04 pm UTC
Forum: Individual XKCD Comic Threads
Topic: 2164: "Glacier"
Replies: 15
Views: 1909

### Re: 2164: "Glacier"

The Sword in the Stone is a legend about how a young King Arthur became King because he was the only person capable of pulling the sword Excalibur out of the stone into which it was stuck via an enchantment to the effect that only the rightful king would be able to pull it out. I believe legends di...
Wed Jun 26, 2019 11:33 am UTC
Forum: Individual XKCD Comic Threads
Topic: 2164: "Glacier"
Replies: 15
Views: 1909

### Re: 2164: "Glacier"

The Sword in the Stone is a legend about how a young King Arthur became King because he was the only person capable of pulling the sword Excalibur out of the stone into which it was stuck via an enchantment to the effect that only the rightful king would be able to pull it out. I believe legends di...
Mon Mar 04, 2019 7:51 pm UTC
Forum: Individual XKCD Comic Threads
Topic: 2118: "Normal Distribution"
Replies: 15
Views: 4417

### Re: 2118: "Normal Distribution"

I'm surprised no-one's explained Randall's maths. Call h the height of the Normal distribution pdf at zero (the mean), ie h = 1/sqrt(2pi). Then the horizontal lines meet the pdf at say (+/-a, h(1-p/2)) and (+/-b, h(1+p/2)) (lower line and upper line respectively). If p = 0.52682, then a = 1.69790 an...

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