My Number is Bigger! (again)
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My Number is Bigger! (again)
This is another version of the "My Number is Bigger!" thread. Here are the rules:
Your number must be bigger than the last number
Your number must be finite (FGH ordinals are allowed, but only if used in the FGH)
Uncomputable numbers are allowed, so long as you can prove they are bigger.
Also, try not to go too big too fast. Jumping from a function of order w to one of order w^w is probably not recommended. This is more a suggestion than a rule.
I'll start:
0
Your number must be bigger than the last number
Your number must be finite (FGH ordinals are allowed, but only if used in the FGH)
Uncomputable numbers are allowed, so long as you can prove they are bigger.
Also, try not to go too big too fast. Jumping from a function of order w to one of order w^w is probably not recommended. This is more a suggestion than a rule.
I'll start:
0
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Re: My Number is Bigger! (again)
0.000000000000000000000000000000000020000000000000000018923
If it looks like a duck, and quacks like a duck, we have at least to consider the possibility that we have a small aquatic bird of the family Anatidae on our hands. –Douglas Adams
 Vytron
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Re: My Number is Bigger! (again)
0.000000000000000000000000000000000020000000000000000018923
000000000000000000000000000000000020000000000000000018923
(without line breaks)
000000000000000000000000000000000020000000000000000018923
(without line breaks)

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 phillip1882
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Re: My Number is Bigger! (again)
Ooh! We have a speedy!
sqrt(6)/2
about 1.225
sqrt(6)/2
about 1.225
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 Vytron
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Re: My Number is Bigger! (again)
(pi3)*10

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Re: My Number is Bigger! (again)
3830101^(1/41)
(1.447)
(1.447)

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Re: My Number is Bigger! (again)
How did you find a number that close, with a formula like that?
1.45
1.45
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 phillip1882
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 Vytron
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Re: My Number is Bigger! (again)
username5243 wrote:How did you find a number that close, with a formula like that?
I wonder if it's "a formula like that" or trial and error (I could get arbitrarily close to a number by trial and error on the other thread.)
10.00000100000000001
Re: My Number is Bigger! (again)
10.10101010101
If it looks like a duck, and quacks like a duck, we have at least to consider the possibility that we have a small aquatic bird of the family Anatidae on our hands. –Douglas Adams
 Vytron
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Re: My Number is Bigger! (again)
10.11011011011011011
 phillip1882
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 Posts: 49
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 Posts: 49
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 Posts: 49
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 Vytron
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Re: My Number is Bigger! (again)
Well, the rules don't disallow referrencing other numbers on the thread, so I'll define:
f(n)=n+x
Where:
x = the second number posted on the thread.
(x=0.000000000000000000000000000000000020000000000000000018923)
Send:
f(1250)
(that is, 1250.000000000000000000000000000000000020000000000000000018923)
f(n)=n+x
Where:
x = the second number posted on the thread.
(x=0.000000000000000000000000000000000020000000000000000018923)
Send:
f(1250)
(that is, 1250.000000000000000000000000000000000020000000000000000018923)

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 Vytron
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Re: My Number is Bigger! (again)
Define:
n. (i.e. any number followed by a .) as f(n)
Send
1251.
(1251.=f(1251)=
1251.000000000000000000000000000000000020000000000000000018923)
n. (i.e. any number followed by a .) as f(n)
Send
1251.
(1251.=f(1251)=
1251.000000000000000000000000000000000020000000000000000018923)

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Re: My Number is Bigger! (again)
I didn't, because if we could, we technically couldn't reference 1 or 10.
I'll introduce the FGH:
f0(n) = n+1
f1(n) = f0(f0(f0(...f0(n)...))) with n nestings = 2n
that's all we nead right now.
submit f1(626) = 1252
I'll introduce the FGH:
f0(n) = n+1
f1(n) = f0(f0(f0(...f0(n)...))) with n nestings = 2n
that's all we nead right now.
submit f1(626) = 1252
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Re: My Number is Bigger! (again)
I introduce my Unreadable Notation, because for some reason, people find it unreadable no matter how I explain it. But please, if you can't read it, explain where exactly you get stuck.
We begin at:
<x>=xx...xx for n+1 copies
And:
n, = <(>n+1<)<+n>>
That is:
0,=n+1=
1,=<(>1+1<)<+1>>=((2)+1+1)+1+1=6
2,=<(>3<)<+2>>=<(((3)+2+2+2)+2+2+2)+2+2+2=21
3,=<(>4<)<+3>>=(4)+3+3+3+3)+3+3+3+3)+3+3+3+3)+3+3+3+3=52
And so on.
n, = n^3+2n^2+2n+1
Next, when you find a 0 after a ,:
n,x0 = <(>n+1<),x>
0,0 = (0+1), = 1,=<(>1+1<)<+1>>=((2)+1+1)+1+1=6
1,0 = ((2),), = (21), = 10195
So, huh:
(1,0)/8
We begin at:
<x>=xx...xx for n+1 copies
And:
n, = <(>n+1<)<+n>>
That is:
0,=n+1=
1,=<(>1+1<)<+1>>=((2)+1+1)+1+1=6
2,=<(>3<)<+2>>=<(((3)+2+2+2)+2+2+2)+2+2+2=21
3,=<(>4<)<+3>>=(4)+3+3+3+3)+3+3+3+3)+3+3+3+3)+3+3+3+3=52
And so on.
n, = n^3+2n^2+2n+1
Next, when you find a 0 after a ,:
n,x0 = <(>n+1<),x>
0,0 = (0+1), = 1,=<(>1+1<)<+1>>=((2)+1+1)+1+1=6
1,0 = ((2),), = (21), = 10195
So, huh:
(1,0)/8

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Re: My Number is Bigger! (again)
Okay, sounds good so far.
So, 2,0 would be (((3),),), equals ((52),), = (146121), ~ 3.12*10^15?
So, each number in the x,0 series seems to be about the cube of the last one, or about exponential growth.
Anyway I'll start on my own notation:
Define:
n[0] = 10^n
n$[m+1] = n$[m][m][m]...[m][m] with n [m]s
Where $ is anything.
Note that n[m] is equal to En##(m+1) in Extended HyperE Notation.
I submit 4[0]/7 ~ 1428.57
So, 2,0 would be (((3),),), equals ((52),), = (146121), ~ 3.12*10^15?
So, each number in the x,0 series seems to be about the cube of the last one, or about exponential growth.
Anyway I'll start on my own notation:
Define:
n[0] = 10^n
n$[m+1] = n$[m][m][m]...[m][m] with n [m]s
Where $ is anything.
Note that n[m] is equal to En##(m+1) in Extended HyperE Notation.
I submit 4[0]/7 ~ 1428.57
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 Vytron
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Re: My Number is Bigger! (again)
username5243 wrote:So, each number in the x,0 series seems to be about the cube of the last one, or about exponential growth.
Um, the cube of 6 is 216, while we get 10195 which is more than ^5ing.
10,0 = (((((((((((11),),),),),),),),),),),
=((((((((((1221),),),),),),),),),),
=(((((((((1823300986),),),),),),),),),
=((((((((6x10^27),),),),),),),),
=(((((((6x10^81),),),),),),),
=((((((6x10^243),),),),),),
=(((((6x10^729),),),),),
=((((6x10^2187),),),),
=(((6x10^6561),),),
=((6x10^19683),),
=(6x10^59049),
=6x10^177147
The equivalent of exponential growth would be:
(((((((((((11)^2)^2)^2)^2)^2)^2)^2)^2)^2)^2)^2
=6x10^2132
Send:
(1,0)/7

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Re: My Number is Bigger! (again)
Somewhere about x^x^x then.
Submit 3[0]*2 = 2000.
Submit 3[0]*2 = 2000.
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Re: My Number is Bigger! (again)
username5243 wrote:Somewhere about x^x^x then.
Yes, close to x^x^(x/2)
Submit:
(1,0)/5

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Re: My Number is Bigger! (again)
(1,0)/4

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Re: My Number is Bigger! (again)
(1,0)/3

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Re: My Number is Bigger! (again)
Clearly we need to get bigger!
9001
OVER NINE THOUSAND!!!
Also the first number in the first "My Number is Bigger" thread.
9001
OVER NINE THOUSAND!!!
Also the first number in the first "My Number is Bigger" thread.
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