Count up using the Busy Beaver function

For all your silly time-killing forum games.

Moderators: jestingrabbit, Moderators General, Prelates

User avatar
WarDaft
Posts: 1583
Joined: Thu Jul 30, 2009 3:16 pm UTC

Count up using the Busy Beaver function

Postby WarDaft » Sun Jun 28, 2015 12:03 am UTC

Specifically, you may use the operations /,-,+,*,^,BB(), grouping via parentheses, and the value 1; where BB(n) is the maximum number of shifts of a 2-symbol n-state Turing Machine.

Here, let me get things started:

BB(1)/(1+1+1+1+1+1)
All Shadow priest spells that deal Fire damage now appear green.
Big freaky cereal boxes of death.

User avatar
Vytron
Posts: 429
Joined: Mon Oct 19, 2009 10:11 am UTC
Location: The Outside. I use She/He/Her/His/Him as gender neutral pronouns :P

Re: Count up using the Busy Beaver function

Postby Vytron » Sun Jun 28, 2015 8:40 am UTC

Um...

BB(1)/(1+1+1+1+1)

?

Notes
Spoiler:
WarDaft's starting value of BB(1)/(1+1+1+1+1+1) is surprising, as it's equal to 1/6.

What I expected Counting up using the Busy Beaver function to look like (among other values):

BB(1) or BB(1+1+1)/(1+1+1+1+1+1)
BB(1)+1 or BB(1+1)/(1+1)
BB(1)+1+1 or BB(1+1)/(1+1)+1
BB(1+1)
BB(1+1)+BB(1) or BB(1+1+1)-1
BB(1+1+1)
BB(1+1+1)+1 or BB(1+1+1+1)-BB(1+1+1)
BB(1+1)*(1+1)
BB(1+1+1)+(BB(1+1+1)/(1+1))
BB(1+1)+BB(1+1+1)
...

PsiSquared
Posts: 126
Joined: Wed May 09, 2012 6:02 pm UTC

Re: Count up using the Busy Beaver function

Postby PsiSquared » Tue Jun 30, 2015 10:37 pm UTC

BB(1+1)/(1+1)
(that's 3)

Spoiler:
The number of shifts for the n-th busy beaver is:
S(1)=1
S(2)=6
S(3)=21
S(4)=107
The OP seems to confuse S(n+1) with S(n) (he also implied S(3)=107 on another thread, where he wrote S(3)^2=11449).

User avatar
faubiguy
Posts: 15
Joined: Sun Aug 11, 2013 9:20 am UTC

Re: Count up using the Busy Beaver function

Postby faubiguy » Thu May 12, 2016 9:57 pm UTC

1+1+1+1

If the use of BB is necessary, BB(1+1)-1-1


Return to “Forum Games”

Who is online

Users browsing this forum: No registered users and 30 guests