Hi, I was working through some questions in my textbook when i came across this one which i can't quite prove.

The question is as follows:

Prove that: (secA-tanA)(secA+tanA) / cosecA-cotA = cotA+cosecA

So far I have got as far as: sec^2(A)-tan^2(A)/cosecA-cotA

Could someone please point me in the right direction to go from here? ( I don't want a full proof, just a hint at where to go )

Thanks for your time.

## Need help proving a trigometric identity

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### Need help proving a trigometric identity

Last edited by voice on Thu Oct 09, 2008 10:47 pm UTC, edited 2 times in total.

### Re: Trigometric proving problem

Well, the first thing I notice is sec

^{2}A-tan^{2}A. Does that simplify to anything?- NathanielJ
**Posts:**882**Joined:**Sun Jan 13, 2008 9:04 pm UTC

### Re: Trigometric proving problem

For questions like this it's almost always best to write everything out in terms of cos and sin, IMO. It makes spotting identities so much easier. sec

^{2}A - tan^{2}A might look scary, but when written in terms of cos and sin it gets demoted to "standard".### Re: Trigometric proving problem

Seconded. In general, transferring the problem to the world of sines and cosines is a good problem-solving approach.

Yakk wrote:It is clear you can reduce Well Ordering to the well known Traveling Salesman problem (you determine the order you visit the wells like the salesman does the cities). But TSP is NP -- not possible -- so Well Ordering is wrong.

### Re: Trigometric proving problem

Buttons wrote:Well, the first thing I notice is sec^{2}A-tan^{2}A. Does that simplify to anything?

Yes. It simplifies to 1, but I don't see where to go from there. cos^2(x)+sin^2(x)=1 perhaps?

NathanielJ wrote:For questions like this it's almost always best to write everything out in terms of cos and sin, IMO. It makes spotting identities so much easier. sec^{2}A - tan^{2}A might look scary, but when written in terms of cos and sin it gets demoted to "standard".

Sabatini wrote:Seconded. In general, transferring the problem to the world of sines and cosines is a good problem-solving approach.

Thanks for the advice, I'll see what i can do...

### Re: Need help proving a trigometric identity

If you haven't got it yet: Do you notice anything interesting about the denominator of your left hand side and your right hand side, that would give you an opportunity to simplify further?

Note that I'm assuming you messed up your parentheses and that the denominator is meant to be (csc-cot), not (csc) with the -cot outside the fraction.

Note that I'm assuming you messed up your parentheses and that the denominator is meant to be (csc-cot), not (csc) with the -cot outside the fraction.

### Re: Need help proving a trigometric identity

Maybe a conjugate or three?

Yakk wrote:It is clear you can reduce Well Ordering to the well known Traveling Salesman problem (you determine the order you visit the wells like the salesman does the cities). But TSP is NP -- not possible -- so Well Ordering is wrong.

### Re: Need help proving a trigometric identity

It can be broken down in the following way:

=(((1/cosA)-(sinA/cosA))((1/cosA)+(sinA/cosA)))/((1/sinA)-(cosA/sinA))=((1-sinA)(1+sinA)(sinA))/((cos^2A)(1-cosA))

=((1-sin^2A)(sinA))/((cos^2A)(1-cosA))

=((cos^2A)(sinA))/((cos^2A)(1-cosA))

=(sinA)/(1-cosA)

=((1+cosA)(sinA))/((1+cosA)(1-cosA))

=((sinA+cosAsinA))/((1-cos^2A))

=((sinA+cosAsinA))/((sin^2A))

=cscA+cotA

=(((1/cosA)-(sinA/cosA))((1/cosA)+(sinA/cosA)))/((1/sinA)-(cosA/sinA))=((1-sinA)(1+sinA)(sinA))/((cos^2A)(1-cosA))

=((1-sin^2A)(sinA))/((cos^2A)(1-cosA))

=((cos^2A)(sinA))/((cos^2A)(1-cosA))

=(sinA)/(1-cosA)

=((1+cosA)(sinA))/((1+cosA)(1-cosA))

=((sinA+cosAsinA))/((1-cos^2A))

=((sinA+cosAsinA))/((sin^2A))

=cscA+cotA

### Re: Need help proving a trigometric identity

macyran wrote:It can be broken down in the following way:

=(((1/cosA)-(sinA/cosA))((1/cosA)+(sinA/cosA)))/((1/sinA)-(cosA/sinA))=((1-sinA)(1+sinA)(sinA))/((cos^2A)(1-cosA))

=((1-sin^2A)(sinA))/((cos^2A)(1-cosA))

=((cos^2A)(sinA))/((cos^2A)(1-cosA))

=(sinA)/(1-cosA)

=((1+cosA)(sinA))/((1+cosA)(1-cosA))

=((sinA+cosAsinA))/((1-cos^2A))

=((sinA+cosAsinA))/((sin^2A))

=cscA+cotA

Whoa! Did you just give him a complete solution of a homework problem?

Yakk wrote:It is clear you can reduce Well Ordering to the well known Traveling Salesman problem (you determine the order you visit the wells like the salesman does the cities). But TSP is NP -- not possible -- so Well Ordering is wrong.

### Re: Need help proving a trigometric identity

Here's a (hopefully) helpful hint.

You were on the rigfht track with what you did so far ....try multiplying out the denominator on the LHS then using the trigonometric identities 1+ cot^2(A)=cosec(A), and sec^(A) = tan@(A)+1. You should get LHS=RHS=1

You were on the rigfht track with what you did so far ....try multiplying out the denominator on the LHS then using the trigonometric identities 1+ cot^2(A)=cosec(A), and sec^(A) = tan@(A)+1. You should get LHS=RHS=1

### Re: Need help proving a trigometric identity

Perhaps my advice is superfluous, but depending on your level it might be ok to

1) Write everything in terms of sines and cosines

2) Use e^x=cos(x)+i*sin(x) to write everything in terms of exponentials

3) Replace cos(x) by a and sin(x) by b

4) Simplify a fraction! Make sure you remember that i^2=-1

5) Change back into sines and cosines.

1) Write everything in terms of sines and cosines

2) Use e^x=cos(x)+i*sin(x) to write everything in terms of exponentials

3) Replace cos(x) by a and sin(x) by b

4) Simplify a fraction! Make sure you remember that i^2=-1

5) Change back into sines and cosines.

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The reason I would kill penguins would be, no one ever, ever fucking kills penguins.

### Re: Need help proving a trigometric identity

If you'd like another hint:

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