Hey guys... I have a math final today and I've been studying but can't figure out this one probability question
The question is... How many different 5 card hands can be dealt from a deck that has only red cards?????
I've tried all sorts of techniques and never seem to get the right answer which is (65,780)
Its killing me cause its so simple but I can't figure it out
Many thanks...
Probability Question
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Re: Probability Question
Unconventional solution: Google "65780 cards", click on the link that talks about dealing cards from a deck, find the comment with the number you're interested in, see what the comment has to say.
GENERATION 1i: The first time you see this, copy it into your sig on any forum. Square it, and then add i to the generation.
 CueBall
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Re: Probability Question
There are only 26 red cards. So, I think the answer is thus.
First, it can be one of 26. Then 25. then 24. etc.
so 26 x 25 x 24 x 23 x 22 which = 7893600.
That, divided by the number of ways those 5 cards can be arranged (120) will give your answer.
First, it can be one of 26. Then 25. then 24. etc.
so 26 x 25 x 24 x 23 x 22 which = 7893600.
That, divided by the number of ways those 5 cards can be arranged (120) will give your answer.
Spoiler:
Re: Probability Question
Thank you cueball!
It all makes so much sense now...
*Commences kicking myself*
It all makes so much sense now...
*Commences kicking myself*
Re: Probability Question
Isn't this a combination question?
26C5=65780
Where Combination is
xCn=[X+(x1)+(x2)...+(x{n1})]/n
26C5=65780
Where Combination is
xCn=[X+(x1)+(x2)...+(x{n1})]/n
 NathanielJ
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 Joined: Sun Jan 13, 2008 9:04 pm UTC
Re: Probability Question
534n wrote:Isn't this a combination question?
26C5=65780
Where Combination is
xCn=[X+(x1)+(x2)...+(x{n1})]/n
Yep, CueBall's answer basically goes through the derivation of what a combination is. Whichever method works for you.
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