lim (-3x

^{2}+5x+2)/|2-x|

x->2

^{+}

If you plug in 2, you end up with 0/0. So I decided to factor the quadratic into (x-2)(x+2/3). My memory is kind of fuzzy, but I remember doing something with the absolute values where you do the equation with the regular argument and then again with the negative argument. So I ended up with (x-2)(x+2/3)/(x-2) or (x-2)(x+2/3)/(2-x). Now, if you plug 2 back into those after canceling the (x-2)'s, you end up with 8/3 or -8/3. Now, looking at the graph, I know that the answer is -8/3. However, we're not supposed to use the graph to solve the problem. So, my question is how do I figure out whether 8/3 or -8/3 is correct without using the graph?