Carlington (The Aussie) wrote:What would be the most simple way to verify this theory? Test if the Earth itself generates neutrinos. Why can't we do this? Because of the sheer number of solar neutrinos passing through the experiment. They would generate so much interference as to render our tests useless.
I don't know jack shit about quantum physics either, so your idea sounded at least plausible. However, I thought through this statement a little more carefully, and you may (or may not) be interested in the results:
Suppose neutrinos are
gravitons. In that case, neutrino flux through the local area from a given source must be proportional to the strength of the gravitational field from that source. The earth's gravitational field strength at the surface is 9.8m/s/s, as we all know. Typing "(G * mass of sun)/(1 AU)^2" (sans quotes) into Google's search bar yields .0059 m/s/s. Therefore, neutrinos from the Earth should massively dwarf neutrinos from the Sun. However, this is not the case, so neutrinos are not gravitons.
Good try though, keep thinking.
Wait on, I think you misunderstood me a bit, or you made a mistake. Or I misunderstood you, it could really go either way. You've gone (G*mass of sun)/(1 AU)^2 = .0059 m/s^2
In other words: F/d^2 = a
Now, checking that with units, we get: kg*m*s^(-2)*m^(-2) = m*s^(-2)
Simplifying: kg*m^(-1)*s^(-2) = m*s^(-2)
and that's not a true statement. I don't doubt that I'm incorrect on other fronts, i.e. I was incorrect in my assumptions that neutrinos have no mass and don't interact, as gmalivuk, Tass and JWalker explained, but I thought I'd point out that your logic is a touch flawed, scarecrovv.
within a transverse wave there lies a longitudinal wave, and that this is how we draw our amplitude vs. time graphs for sound waves
Not to get off topics, but what do you mean by this? ...
Well, it only really applies to standing waves now that I think about it.
In that (shoddy, 30-second, MSPaint
) diagram, A is a node, B and C are the maximum and zero amplitudes of the antinode.
As the shape of the wave rotates from AB to AC, our approximaton shows us that the distance between these two points fluctuates periodically with the motion of the transverse wave. Remembering that none of the individual particles in a transverse wave actually move in the direction of propagation, this change in distance between the two points must therefore represent compressions and rarefactions. Knowing as we do that compressions and rarefactions mean longitudinal wave, we can see that within this transverse standing wave there lies a longitudinal wave. According to my physics teacher, (who has lied to make the answers to my questions easier before) we use the reverse of this process to graphicaly represent the amplitude over time of a compressional wave, usually a sound wave.