(a-b)

^{2}+ (c-d)

^{2}+ (e-f)

^{2}And all this under a square root

(this is Osgood semantic differential)

I'm doing it just like

(10-5)

^{2}+ (4-2)

^{2}+ (6-3)

^{2}

25 + 4 + 9

38 sq root= 6.164...

correct?

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- gaurwraith
**Posts:**285**Joined:**Fri Jul 27, 2007 3:56 pm UTC

Hello, would someone please be so kind as to tell me if I'm doing ok or lead me in how to solve this formula:

(a-b)^{2} + (c-d)^{2} + (e-f)^{2} And all this under a square root

(this is Osgood semantic differential)

I'm doing it just like

(10-5)^{2} + (4-2)^{2} + (6-3)^{2}

25 + 4 + 9

38 sq root= 6.164...

correct?

(a-b)

(this is Osgood semantic differential)

I'm doing it just like

(10-5)

25 + 4 + 9

38 sq root= 6.164...

correct?

I am a lvl 89 sword barb

Solve the formula for what?

And also, when you say formula, do you mean you have something like y=sqrt( (a-b)^2 + (c-d)^2 + (e-f)^2)? As it's just an expression rather then an equation unless you have an equals sign somewhere.

Are a,b,c,...,f known constants?

If you mean solve the equation y=sqrt( (a-b)^2 + (c-d)^2 + (e-f)^2) for y, then that is 'solved' in that form already, and can't be simplified any further unless some of a,b,c,d,e,f are related. If you have specific values for those variables, then you can sub them in as you did in your post to get a particular number (e.g. sqrt(38) if a=10, b=5, c=4, d=2, e=6, and f=3).

I will mention I'm not familiar with the idea of a Osgood semantic differential however, and wikipedia didn't help much, so perhaps theres something I'm missing about your question. (Also, help desk is usually for tech help, and this is more of a math help thing so far as I can tell. Again, perhaps I'm missing something that makes it more tech-y, but it looks like this might be more at home in math land.)

And also, when you say formula, do you mean you have something like y=sqrt( (a-b)^2 + (c-d)^2 + (e-f)^2)? As it's just an expression rather then an equation unless you have an equals sign somewhere.

Are a,b,c,...,f known constants?

If you mean solve the equation y=sqrt( (a-b)^2 + (c-d)^2 + (e-f)^2) for y, then that is 'solved' in that form already, and can't be simplified any further unless some of a,b,c,d,e,f are related. If you have specific values for those variables, then you can sub them in as you did in your post to get a particular number (e.g. sqrt(38) if a=10, b=5, c=4, d=2, e=6, and f=3).

I will mention I'm not familiar with the idea of a Osgood semantic differential however, and wikipedia didn't help much, so perhaps theres something I'm missing about your question. (Also, help desk is usually for tech help, and this is more of a math help thing so far as I can tell. Again, perhaps I'm missing something that makes it more tech-y, but it looks like this might be more at home in math land.)

It looks like basically the Euclidean distance between the points (a,c,e) and (b,d,f).

she/they

gmalivuk wrote:Yes. And if wishes were horses, wishing wells would fill up very quickly with drowned horses.King Author wrote:If space (rather, distance) is an illusion, it'd be possible for one meta-me to experience both body's sensory inputs.

- gaurwraith
**Posts:**285**Joined:**Fri Jul 27, 2007 3:56 pm UTC

My sincere thanks to both of you, I can now proclame this question solved.

thanks.

thanks.

I am a lvl 89 sword barb

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