Sorry about the diagram, I just did it quickly in GIMP.

As shown in the image above:

ABC is defined as a right angle;

BCD is defines as 90 degrees minus x;

AB and CD are defined to be of equal length;

G is defined as the point where the two perpendicular bisectors (EG and FG) meet;

As ADG is isosceles AG and DG are clearly equal;

As BCG is isosceles BG and CG are clearly equal;

Angle GBC and angle BCG are clearly equal due to being on the inside of an isosceles;

(GBC=BCG)

Triangles ABG and CDG are congruent so angle ABG is equal to angle DCG;

(ABG=DCG)

ABG+GBC=DCG+BCG

90=90-x

???

## Maths is broken Mk II

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### Re: Maths is broken Mk II

**Spoiler:**

In the spirit of taking things too far - the 5x5x5x5x5 Rubik's Cube.

### Re: Maths is broken Mk II

Alky wrote:Spoiler:

If D is left of C, why would F not be left of E?

All posts are works in progress. If I posted something within the last hour, chances are I'm still editing it.

### Re: Maths is broken Mk II

**Spoiler:**

Last edited by Seraph on Fri Oct 12, 2007 1:17 pm UTC, edited 1 time in total.

### Re: Maths is broken Mk II

**Spoiler:**

### Re: Maths is broken Mk II

Here's a to-scale version, for some value of X I didn't bother to calculate.

And with the triangles in red and moved aside for easy viewing:

**Spoiler:**

And with the triangles in red and moved aside for easy viewing:

**Spoiler:**

There are two types of people in the world: 1) those that can extrapolate from incomplete data.

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